What are the solutions to the equation factor x^2+13x=-42 ?

The solutions to the equation factor x^2+13x=-42 are x=-6,x=-7

Find the zeros of factor x^2+13x=-42

The zeros of factor x^2+13x=-42 are x=-6,x=-7

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x^{2} + 13 x = - 42

x = - 6, x = - 7

Solution steps

x^{2} + 13 x = - 42

Move

42

to the left side

x^{2} + 13 x + 42 = 0

Factor

x^{2} + 13 x + 42 : (x + 6) (x + 7)

(x + 6) (x + 7) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 6 = 0 or x + 7 = 0

Solve

x + 6 = 0 : x = - 6

Solve

x + 7 = 0 : x = - 7

The solutions to the quadratic equation are:

x = - 6, x = - 7

\frac{7}{( x - 3 )}

\frac{49}{36}

x, - 7 = \frac{x}{9}

- 7 \cdot 12

x^{2} + 6 x = 16

What are the solutions to the equation factor x^2+13x=-42 ?
The solutions to the equation factor x^2+13x=-42 are x=-6,x=-7
Find the zeros of factor x^2+13x=-42
The zeros of factor x^2+13x=-42 are x=-6,x=-7