What are the solutions to the equation solvefor x,x(x-3)=40 ?

The solutions to the equation solvefor x,x(x-3)=40 are x=8,x=-5

Find the zeros of solvefor x,x(x-3)=40

The zeros of solvefor x,x(x-3)=40 are x=8,x=-5

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x, x (x - 3) = 40

x = 8, x = - 5

Solution steps

x (x - 3) = 40

Expand

x (x - 3) : x^{2} - 3 x

x^{2} - 3 x = 40

Move

40

to the left side

x^{2} - 3 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 40) = 13

x_{1, 2} = \frac{- ( - 3 ) \pm 13}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 13}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 13}{2 \cdot 1}

x = \frac{- ( - 3 ) + 13}{2 \cdot 1} : 8

x = \frac{- ( - 3 ) - 13}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 8, x = - 5

x^{2} - 6 = x

67%

x, 39 = \frac{180}{x}

y, 2 - \frac{1}{8} y = 11 + \frac{7}{8} y

x^{2} - 2 x = 99

What are the solutions to the equation solvefor x,x(x-3)=40 ?
The solutions to the equation solvefor x,x(x-3)=40 are x=8,x=-5
Find the zeros of solvefor x,x(x-3)=40
The zeros of solvefor x,x(x-3)=40 are x=8,x=-5