What is longdivision ((9x^3-21x^2+18x-29))/((3x-6)) ?

The solution to longdivision ((9x^3-21x^2+18x-29))/((3x-6)) is 3x^2-x+4-5/(3x-6)

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Divide Using Long Polynomial Division (9x^3-21x^2+18x-29)÷(3x-6)

long division

\frac{( 9 x ^{3} - 21 x ^{2} + 18 x - 29 )}{( 3 x - 6 )}

3 x^{2} - x + 4 - \frac{5}{3 x - 6}

Solution steps

\frac{( 9 x ^{3} - 21 x ^{2} + 18 x - 29 )}{( 3 x - 6 )}

Divide

\frac{9 x ^{3} - 21 x ^{2} + 18 x - 29}{3 x - 6} : \frac{9 x ^{3} - 21 x ^{2} + 18 x - 29}{3 x - 6} = 3 x^{2} + \frac{- 3 x ^{2} + 18 x - 29}{3 x - 6}

= 3 x^{2} + \frac{- 3 x ^{2} + 18 x - 29}{3 x - 6}

Divide

\frac{- 3 x ^{2} + 18 x - 29}{3 x - 6} : \frac{- 3 x ^{2} + 18 x - 29}{3 x - 6} = - x + \frac{12 x - 29}{3 x - 6}

= 3 x^{2} - x + \frac{12 x - 29}{3 x - 6}

Divide

\frac{12 x - 29}{3 x - 6} : \frac{12 x - 29}{3 x - 6} = 4 + \frac{- 5}{3 x - 6}

= 3 x^{2} - x + 4 + \frac{- 5}{3 x - 6}

Simplify

= 3 x^{2} - x + 4 - \frac{5}{3 x - 6}

4 x^{2} - 5 x = 0

x, 6 x = 216

x, 3 x - 5 = 16

- 8 x + 10 - 3 x^{2} = - 12 x

- \frac{23}{4}

What is longdivision ((9x^3-21x^2+18x-29))/((3x-6)) ?
The solution to longdivision ((9x^3-21x^2+18x-29))/((3x-6)) is 3x^2-x+4-5/(3x-6)