What is the answer to solvefor x,10^{-x}=11 ?

The answer to solvefor x,10^{-x}=11 is x=-(ln(11))/(ln(10))

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Solve for x 10^(-x)=11

solve for

x, 1 0^{- x} = 11

x = - \frac{ln ( 11 )}{ln ( 10 )}

Decimal Notation

x = - 1.04139 \dots

Solution steps

1 0^{- x} = 11

Apply exponent rules

- x ln (10) = ln (11)

Solve

- x ln (10) = ln (11) : x = - \frac{ln ( 11 )}{ln ( 10 )}

x = - \frac{ln ( 11 )}{ln ( 10 )}

x (\frac{1}{2 x ^{\frac{- 1}{2}}})

x^{2} - 48 = 0

x, 2^{x} = 11

1.17 - 0.07 a + (- 3.92 a)

x, x - 47 = - 25

What is the answer to solvefor x,10^{-x}=11 ?
The answer to solvefor x,10^{-x}=11 is x=-(ln(11))/(ln(10))