What are the solutions to the equation quadraticformula 2x^2-x-6=0 ?

The solutions to the equation quadraticformula 2x^2-x-6=0 are x=2,x=-3/2

Find the zeros of quadraticformula 2x^2-x-6=0

The zeros of quadraticformula 2x^2-x-6=0 are x=2,x=-3/2

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2 x^{2} - x - 6 = 0

x = 2, x = - \frac{3}{2}

Decimal Notation

x = 2, x = - 1.5

Solution steps

2 x^{2} - x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 6) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 2}

x = \frac{- ( - 1 ) + 7}{2 \cdot 2} : 2

x = \frac{- ( - 1 ) - 7}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = - \frac{3}{2}

\frac{1}{( x - 1 )} + \frac{1}{( 4 x - 4 )} = \frac{5}{4}

16 (- 8)

3 x^{2} + 26 x - 9

\frac{4}{( 3 )}

42%

What are the solutions to the equation quadraticformula 2x^2-x-6=0 ?
The solutions to the equation quadraticformula 2x^2-x-6=0 are x=2,x=-3/2
Find the zeros of quadraticformula 2x^2-x-6=0
The zeros of quadraticformula 2x^2-x-6=0 are x=2,x=-3/2