What is factor 20y^6-15y^4+40y^2 ?

The solution to factor 20y^6-15y^4+40y^2 is 5y^2(4y^4-3y^2+8)

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factor 20y^6-15y^4+40y^2

factor

20 y^{6} - 15 y^{4} + 40 y^{2}

5 y^{2} (4 y^{4} - 3 y^{2} + 8)

Solution steps

20 y^{6} - 15 y^{4} + 40 y^{2}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

y^{4} = y^{2} y^{2}

= 20 y^{4} y^{2} - 15 y^{2} y^{2} + 40 y^{2}

Rewrite

20

5 \cdot 4

Rewrite

15

5 \cdot 3

= 5 \cdot 4 y^{4} y^{2} - 5 \cdot 3 y^{2} y^{2} + 5 \cdot 8 y^{2}

Factor out common term

5 y^{2}

= 5 y^{2} (4 y^{4} - 3 y^{2} + 8)

\frac{5}{x - 5} > 1

∣ 2 x - 3 ∣ = 11

6 x - 48 = 4 x + 38

2 (x + 3)^{2} = 24

3 (x - 4) = 4 - 2 (x + 2)

What is factor 20y^6-15y^4+40y^2 ?
The solution to factor 20y^6-15y^4+40y^2 is 5y^2(4y^4-3y^2+8)