What are the solutions to the equation 12x^2-10=0 ?

The solutions to the equation 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)

Find the zeros of 12x^2-10=0

The zeros of 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)

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12 x^{2} - 10 = 0

x = \frac{5}{6}, x = - \frac{5}{6}

Solution steps

12 x^{2} - 10 = 0

Move

10

to the right side

12 x^{2} = 10

Divide both sides by

12

x^{2} = \frac{5}{6}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{6}, x = - \frac{5}{6}

4 x^{2} + 29 x + 30

\frac{3 x - 8}{2} \geq 4

x^{2} + 22 x + 21 = 0

- 1.2 (w + 1.1) \leq 6.18

\frac{x ^{2}}{x ^{\frac{2}{3}}}

What are the solutions to the equation 12x^2-10=0 ?
The solutions to the equation 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)
Find the zeros of 12x^2-10=0
The zeros of 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)