What are the solutions to the equation 12x^2-10=0 ?

The solutions to the equation 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)

Find the zeros of 12x^2-10=0

The zeros of 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

12 x^{2} - 10 = 0

x = \frac{5}{6}, x = - \frac{5}{6}

Decimal Notation

x = 0.91287 \dots, x = - 0.91287 \dots

Solution steps

12 x^{2} - 10 = 0

Move

10

to the right side

12 x^{2} = 10

Divide both sides by

12

x^{2} = \frac{5}{6}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{5}{6}, x = - \frac{5}{6}

4 x^{2} + 29 x + 30

\frac{3 x - 8}{2} \geq 4

x^{2} + 22 x + 21 = 0

- 1.2 (w + 1.1) \leq 6.18

\frac{x ^{2}}{x ^{\frac{2}{3}}}

What are the solutions to the equation 12x^2-10=0 ?
The solutions to the equation 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)
Find the zeros of 12x^2-10=0
The zeros of 12x^2-10=0 are x=sqrt(5/6),x=-sqrt(5/6)