What are the solutions to the equation x^2+22x+21=0 ?

The solutions to the equation x^2+22x+21=0 are x=-1,x=-21

Find the zeros of x^2+22x+21=0

The zeros of x^2+22x+21=0 are x=-1,x=-21

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x^{2} + 22 x + 21 = 0

x = - 1, x = - 21

Solution steps

x^{2} + 22 x + 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 1 \cdot 21}{2 \cdot 1}

2 2^{2} - 4 \cdot 1 \cdot 21 = 20

x_{1, 2} = \frac{- 22 \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 22 + 20}{2 \cdot 1}, x_{2} = \frac{- 22 - 20}{2 \cdot 1}

x = \frac{- 22 + 20}{2 \cdot 1} : - 1

x = \frac{- 22 - 20}{2 \cdot 1} : - 21

The solutions to the quadratic equation are:

x = - 1, x = - 21

- 1.2 (w + 1.1) \leq 6.18

\frac{x ^{2}}{x ^{\frac{2}{3}}}

m^{2} + m + 4 = 0

- 8 i (9 + 4 i)

2 x^{2} + 22 x + 48

What are the solutions to the equation x^2+22x+21=0 ?
The solutions to the equation x^2+22x+21=0 are x=-1,x=-21
Find the zeros of x^2+22x+21=0
The zeros of x^2+22x+21=0 are x=-1,x=-21