What are the solutions to the equation m^2+m+4=0 ?

The solutions to the equation m^2+m+4=0 are m=-1/2+i(sqrt(15))/2 ,m=-1/2-i(sqrt(15))/2

Find the zeros of m^2+m+4=0

The zeros of m^2+m+4=0 are m=-1/2+i(sqrt(15))/2 ,m=-1/2-i(sqrt(15))/2

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m^{2} + m + 4 = 0

m = - \frac{1}{2} + i \frac{15}{2}, m = - \frac{1}{2} - i \frac{15}{2}

Solution steps

m^{2} + m + 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 4 : 15 i

m_{1, 2} = \frac{- 1 \pm 15 i}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 1 + 15 i}{2 \cdot 1}, m_{2} = \frac{- 1 - 15 i}{2 \cdot 1}

m = \frac{- 1 + 15 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{15}{2}

m = \frac{- 1 - 15 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{15}{2}

The solutions to the quadratic equation are:

m = - \frac{1}{2} + i \frac{15}{2}, m = - \frac{1}{2} - i \frac{15}{2}

- 8 i (9 + 4 i)

2 x^{2} + 22 x + 48

9^{2} + 3^{2} = x^{2}

\frac{4}{9} + \frac{1}{2}

5 x^{2} - 10 x + 51 = 6

What are the solutions to the equation m^2+m+4=0 ?
The solutions to the equation m^2+m+4=0 are m=-1/2+i(sqrt(15))/2 ,m=-1/2-i(sqrt(15))/2
Find the zeros of m^2+m+4=0
The zeros of m^2+m+4=0 are m=-1/2+i(sqrt(15))/2 ,m=-1/2-i(sqrt(15))/2