What are the solutions to the equation 5x^2-10x+51=6 ?

The solutions to the equation 5x^2-10x+51=6 are x=1+2sqrt(2)i,x=1-2sqrt(2)i

Find the zeros of 5x^2-10x+51=6

The zeros of 5x^2-10x+51=6 are x=1+2sqrt(2)i,x=1-2sqrt(2)i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 10 x + 51 = 6

x = 1 + 22 i, x = 1 - 22 i

Solution steps

5 x^{2} - 10 x + 51 = 6

Move

6

to the left side

5 x^{2} - 10 x + 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 5 \cdot 45}{2 \cdot 5}

Simplify

(- 10)^{2} - 4 \cdot 5 \cdot 45 : 202 i

x_{1, 2} = \frac{- ( - 10 ) \pm 20 2 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 20 2 i}{2 \cdot 5}, x_{2} = \frac{- ( - 10 ) - 20 2 i}{2 \cdot 5}

x = \frac{- ( - 10 ) + 20 2 i}{2 \cdot 5} : 1 + 22 i

x = \frac{- ( - 10 ) - 20 2 i}{2 \cdot 5} : 1 - 22 i

The solutions to the quadratic equation are:

x = 1 + 22 i, x = 1 - 22 i

∣ - 5 x + 4 ∣ \leq 11

\frac{4}{5} - \frac{4}{6} - \frac{3}{6} + \frac{3}{7}

x - x^{2} + 20 = 0

3 ∣ 3 x - 2 ∣ - 6 = 9

5 x^{2} + 16 x + 12

What are the solutions to the equation 5x^2-10x+51=6 ?
The solutions to the equation 5x^2-10x+51=6 are x=1+2sqrt(2)i,x=1-2sqrt(2)i
Find the zeros of 5x^2-10x+51=6
The zeros of 5x^2-10x+51=6 are x=1+2sqrt(2)i,x=1-2sqrt(2)i