What are the solutions to the equation quadraticformula x^2-9x+20=0 ?

The solutions to the equation quadraticformula x^2-9x+20=0 are x=5,x=4

Find the zeros of quadraticformula x^2-9x+20=0

The zeros of quadraticformula x^2-9x+20=0 are x=5,x=4

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x^{2} - 9 x + 20 = 0

x = 5, x = 4

Solution steps

x^{2} - 9 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 20}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 20 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 1}

x = \frac{- ( - 9 ) + 1}{2 \cdot 1} : 5

x = \frac{- ( - 9 ) - 1}{2 \cdot 1} : 4

The solutions to the quadratic equation are:

x = 5, x = 4

x, 2^{x} = 17

225/25

5 - i

63

x^{2} = 9 x - 14

What are the solutions to the equation quadraticformula x^2-9x+20=0 ?
The solutions to the equation quadraticformula x^2-9x+20=0 are x=5,x=4
Find the zeros of quadraticformula x^2-9x+20=0
The zeros of quadraticformula x^2-9x+20=0 are x=5,x=4