What are the solutions to the equation x-x^2+20=0 ?

The solutions to the equation x-x^2+20=0 are x=-4,x=5

Find the zeros of x-x^2+20=0

The zeros of x-x^2+20=0 are x=-4,x=5

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x - x^{2} + 20 = 0

x = - 4, x = 5

Solution steps

x - x^{2} + 20 = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 1 ) \cdot 20}{2 ( - 1 )}

1^{2} - 4 (- 1) \cdot 20 = 9

x_{1, 2} = \frac{- 1 \pm 9}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 1 + 9}{2 ( - 1 )}, x_{2} = \frac{- 1 - 9}{2 ( - 1 )}

x = \frac{- 1 + 9}{2 ( - 1 )} : - 4

x = \frac{- 1 - 9}{2 ( - 1 )} : 5

The solutions to the quadratic equation are:

x = - 4, x = 5

3 ∣ 3 x - 2 ∣ - 6 = 9

5 x^{2} + 16 x + 12

3 x^{2} - 3 x + 12 = 0

- - 11

3 x^{2} - 192

What are the solutions to the equation x-x^2+20=0 ?
The solutions to the equation x-x^2+20=0 are x=-4,x=5
Find the zeros of x-x^2+20=0
The zeros of x-x^2+20=0 are x=-4,x=5