What are the solutions to the equation quadraticformula x^2-3x-2=0 ?

The solutions to the equation quadraticformula x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

Find the zeros of quadraticformula x^2-3x-2=0

The zeros of quadraticformula x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2

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x^{2} - 3 x - 2 = 0

x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

Solution steps

x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot (- 2) = 17

x_{1, 2} = \frac{- ( - 3 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 17}{2 \cdot 1}

x = \frac{- ( - 3 ) + 17}{2 \cdot 1} : \frac{3 + 17}{2}

x = \frac{- ( - 3 ) - 17}{2 \cdot 1} : \frac{3 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{3 + 17}{2}, x = \frac{3 - 17}{2}

x^{2} = 27

144 x^{2} + 24 x + 1

x, 6 x - 4 = 0

\frac{5}{9 ( x - 32 )}

d, f = \frac{g + 6}{5 d}

What are the solutions to the equation quadraticformula x^2-3x-2=0 ?
The solutions to the equation quadraticformula x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2
Find the zeros of quadraticformula x^2-3x-2=0
The zeros of quadraticformula x^2-3x-2=0 are x=(3+sqrt(17))/2 ,x=(3-sqrt(17))/2