What is the answer to 4(2x-1)+2(3x+1)=5(x+1)-3(6x-1) ?

The answer to 4(2x-1)+2(3x+1)=5(x+1)-3(6x-1) is x= 10/27

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4(2x-1)+2(3x+1)=5(x+1)-3(6x-1)

4 (2 x - 1) + 2 (3 x + 1) = 5 (x + 1) - 3 (6 x - 1)

x = \frac{10}{27}

Decimal Notation

x = 0.37037 \dots

Solution steps

4 (2 x - 1) + 2 (3 x + 1) = 5 (x + 1) - 3 (6 x - 1)

Expand

4 (2 x - 1) + 2 (3 x + 1) : 14 x - 2

Expand

5 (x + 1) - 3 (6 x - 1) : - 13 x + 8

14 x - 2 = - 13 x + 8

Move

2

to the right side

14 x = - 13 x + 10

Move

13 x

to the left side

27 x = 10

Divide both sides by

27

x = \frac{10}{27}

2 x^{2} - 5 x = 25

8 x^{2} + 6 x = 5

\frac{2 m + 3}{2} - \frac{17}{4} < \frac{m + 2}{8}

\frac{7}{5} \cdot 5

x^{2} - 2 x + 2 = 0

What is the answer to 4(2x-1)+2(3x+1)=5(x+1)-3(6x-1) ?
The answer to 4(2x-1)+2(3x+1)=5(x+1)-3(6x-1) is x= 10/27
Solve for x: 4(2x-1)+2(3x+1)=5(x+1)-3(6x-1)
The solution is x= 10/27