What are the solutions to the equation 8x^2+6x=5 ?

The solutions to the equation 8x^2+6x=5 are x= 1/2 ,x=-5/4

Find the zeros of 8x^2+6x=5

The zeros of 8x^2+6x=5 are x= 1/2 ,x=-5/4

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8 x^{2} + 6 x = 5

x = \frac{1}{2}, x = - \frac{5}{4}

Solution steps

8 x^{2} + 6 x = 5

Move

5

to the left side

8 x^{2} + 6 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 8 ( - 5 )}{2 \cdot 8}

6^{2} - 4 \cdot 8 (- 5) = 14

x_{1, 2} = \frac{- 6 \pm 14}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- 6 + 14}{2 \cdot 8}, x_{2} = \frac{- 6 - 14}{2 \cdot 8}

x = \frac{- 6 + 14}{2 \cdot 8} : \frac{1}{2}

x = \frac{- 6 - 14}{2 \cdot 8} : - \frac{5}{4}

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - \frac{5}{4}

\frac{2 m + 3}{2} - \frac{17}{4} < \frac{m + 2}{8}

\frac{7}{5} \cdot 5

x^{2} - 2 x + 2 = 0

12 x^{2} - 25 x + 12 = 0

\frac{5 x}{6} - \frac{x}{3} = \frac{1}{6}

What are the solutions to the equation 8x^2+6x=5 ?
The solutions to the equation 8x^2+6x=5 are x= 1/2 ,x=-5/4
Find the zeros of 8x^2+6x=5
The zeros of 8x^2+6x=5 are x= 1/2 ,x=-5/4