What are the solutions to the equation x^2+2x+93=-6-10x ?

The solutions to the equation x^2+2x+93=-6-10x are x=-6+3sqrt(7)i,x=-6-3sqrt(7)i

Find the zeros of x^2+2x+93=-6-10x

The zeros of x^2+2x+93=-6-10x are x=-6+3sqrt(7)i,x=-6-3sqrt(7)i

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x^{2} + 2 x + 93 = - 6 - 10 x

x = - 6 + 37 i, x = - 6 - 37 i

Solution steps

x^{2} + 2 x + 93 = - 6 - 10 x

Move

10 x

to the left side

x^{2} + 12 x + 93 = - 6

Move

6

to the left side

x^{2} + 12 x + 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 99}{2 \cdot 1}

Simplify

1 2^{2} - 4 \cdot 1 \cdot 99 : 67 i

x_{1, 2} = \frac{- 12 \pm 6 7 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 12 + 6 7 i}{2 \cdot 1}, x_{2} = \frac{- 12 - 6 7 i}{2 \cdot 1}

x = \frac{- 12 + 6 7 i}{2 \cdot 1} : - 6 + 37 i

x = \frac{- 12 - 6 7 i}{2 \cdot 1} : - 6 - 37 i

The solutions to the quadratic equation are:

x = - 6 + 37 i, x = - 6 - 37 i

- x^{2} + x = 0

- 9 \geq - 11 + v

- 3 \leq 2 x - 1 \leq 5

s^{2} - 17 s - 60

What are the solutions to the equation x^2+2x+93=-6-10x ?
The solutions to the equation x^2+2x+93=-6-10x are x=-6+3sqrt(7)i,x=-6-3sqrt(7)i
Find the zeros of x^2+2x+93=-6-10x
The zeros of x^2+2x+93=-6-10x are x=-6+3sqrt(7)i,x=-6-3sqrt(7)i