What are the solutions to the equation quadraticformula x^2-4=5 ?

The solutions to the equation quadraticformula x^2-4=5 are x=3,x=-3

Find the zeros of quadraticformula x^2-4=5

The zeros of quadraticformula x^2-4=5 are x=3,x=-3

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x^{2} - 4 = 5

x = 3, x = - 3

Solution steps

x^{2} - 4 = 5

Move

5

to the left side

x^{2} - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 9) = 6

x_{1, 2} = \frac{- 0 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 6}{2 \cdot 1}, x_{2} = \frac{- 0 - 6}{2 \cdot 1}

x = \frac{- 0 + 6}{2 \cdot 1} : 3

x = \frac{- 0 - 6}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

x = 3, x = - 3

14 x^{2} - 10 x^{2} = 0

130%

x, ∣ x - 3 ∣ = 6

x^{2} - 12 x + 35 = 0

(2 p^{2} + 7 q) (2 p^{2} - 7 q)

What are the solutions to the equation quadraticformula x^2-4=5 ?
The solutions to the equation quadraticformula x^2-4=5 are x=3,x=-3
Find the zeros of quadraticformula x^2-4=5
The zeros of quadraticformula x^2-4=5 are x=3,x=-3