What are the solutions to the equation solvefor y,y^2=x^2(x+1) ?

The solutions to the equation solvefor y,y^2=x^2(x+1) are y=xsqrt(x+1),y=-xsqrt(x+1)

Find the zeros of solvefor y,y^2=x^2(x+1)

The zeros of solvefor y,y^2=x^2(x+1) are y=xsqrt(x+1),y=-xsqrt(x+1)

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solve for

y, y^{2} = x^{2} (x + 1)

y = x x + 1, y = - x x + 1

Solution steps

y^{2} = x^{2} (x + 1)

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = x^{2} (x + 1), y = - x^{2} (x + 1)

Simplify

x^{2} (x + 1) : x x + 1

Simplify

- x^{2} (x + 1) : - x x + 1

y = x x + 1, y = - x x + 1

10 x^{2} - 2 x - 3 = 0

2 x + 1 = 6

x^{2} - 6 x - 27 < 0

82 \cdot 2

lo g_{3} (0.5)

What are the solutions to the equation solvefor y,y^2=x^2(x+1) ?
The solutions to the equation solvefor y,y^2=x^2(x+1) are y=xsqrt(x+1),y=-xsqrt(x+1)
Find the zeros of solvefor y,y^2=x^2(x+1)
The zeros of solvefor y,y^2=x^2(x+1) are y=xsqrt(x+1),y=-xsqrt(x+1)