What is the answer to solvefor x,e^{ln(x^2)}-16=0 ?

The answer to solvefor x,e^{ln(x^2)}-16=0 is x=4,x=-4

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Solve for x e^( natural log of x^2)-16=0

solve for

x, e^{l n (x^{2})} - 16 = 0

x = 4, x = - 4

Solution steps

e^{l n (x^{2})} - 16 = 0

Add

16

to both sides

e^{l n (x^{2})} - 16 + 16 = 0 + 16

Simplify

e^{l n (x^{2})} = 16

Apply exponent rules

ln (x^{2}) = ln (16)

Solve

ln (x^{2}) = ln (16) : x = 4, x = - 4

x = 4, x = - 4

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What is the answer to solvefor x,e^{ln(x^2)}-16=0 ?
The answer to solvefor x,e^{ln(x^2)}-16=0 is x=4,x=-4