What are the solutions to the equation -3x^2+27=0 ?

The solutions to the equation -3x^2+27=0 are x=3,x=-3

Find the zeros of -3x^2+27=0

The zeros of -3x^2+27=0 are x=3,x=-3

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- 3 x^{2} + 27 = 0

x = 3, x = - 3

Solution steps

- 3 x^{2} + 27 = 0

Move

27

to the right side

- 3 x^{2} = - 27

Divide both sides by

- 3

x^{2} = 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 9, x = - 9

9 = 3

- 9 = - 3

x = 3, x = - 3

∣ 3 x - 8 ∣ > - 1

(2 - (2 - k))^{2}

(x + 2)^{2} - 9

e^{i θ} + e^{- i θ}

lo g_{\frac{1}{x}} (2.5 x - 1) \geq - 2

What are the solutions to the equation -3x^2+27=0 ?
The solutions to the equation -3x^2+27=0 are x=3,x=-3
Find the zeros of -3x^2+27=0
The zeros of -3x^2+27=0 are x=3,x=-3