What is factor e^{iθ}+e^{-iθ} ?

The solution to factor e^{iθ}+e^{-iθ} is (cos(-θ)+isin(-θ))(cos(2θ)+isin(2θ)+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor e^{iθ}+e^{-iθ}

factor

e^{i θ} + e^{- i θ}

(cos (- θ) + i sin (- θ)) (cos (2 θ) + i sin (2 θ) + 1)

Solution steps

e^{i θ} + e^{- i θ}

Apply exponent rule:

a^{b + c} = a^{b} a^{c}

e^{i θ} = e^{- i θ} e^{2 i θ}

= e^{- i θ} e^{2 i θ} + e^{- i θ}

Factor out common term

e^{- i θ}

= e^{- i θ} (e^{2 i θ} + 1)

Refine

= (cos (- θ) + i sin (- θ)) (cos (2 θ) + i sin (2 θ) + 1)

lo g_{\frac{1}{x}} (2.5 x - 1) \geq - 2

2 x + 23 = 6 x + 47

2^{k + 1} + 2^{k + 1}

s^{2} - 7 s = 0

- \frac{1}{2} + 9

What is factor e^{iθ}+e^{-iθ} ?
The solution to factor e^{iθ}+e^{-iθ} is (cos(-θ)+isin(-θ))(cos(2θ)+isin(2θ)+1)