What are the solutions to the equation s^2-7s=0 ?

The solutions to the equation s^2-7s=0 are s=7,s=0

Find the zeros of s^2-7s=0

The zeros of s^2-7s=0 are s=7,s=0

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s^{2} - 7 s = 0

s = 7, s = 0

Solution steps

s^{2} - 7 s = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

s_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, s_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

s = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

s = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

s = 7, s = 0

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- 6 + 3 p = 8 p + 2 (1 - 3 p)

s^{2} + 2 s + 4 = 0

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What are the solutions to the equation s^2-7s=0 ?
The solutions to the equation s^2-7s=0 are s=7,s=0
Find the zeros of s^2-7s=0
The zeros of s^2-7s=0 are s=7,s=0