What are the solutions to the equation x^2-20=x ?

The solutions to the equation x^2-20=x are x=5,x=-4

Find the zeros of x^2-20=x

The zeros of x^2-20=x are x=5,x=-4

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x^{2} - 20 = x

x = 5, x = - 4

Solution steps

x^{2} - 20 = x

Move

x

to the left side

x^{2} - 20 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - x - 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 20 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 20) = 9

x_{1, 2} = \frac{- ( - 1 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 9}{2 \cdot 1}

x = \frac{- ( - 1 ) + 9}{2 \cdot 1} : 5

x = \frac{- ( - 1 ) - 9}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 5, x = - 4

4 (2 x^{2} + 1) - 2 (4 x - 1) = 2 (2 x - 1)^{2}

x^{3} - 8 x^{2} + 15 x

\frac{3}{2} + (- \frac{6}{5})

3 (3 v - 8) = 21

\frac{1}{8} = \frac{2}{5} x

What are the solutions to the equation x^2-20=x ?
The solutions to the equation x^2-20=x are x=5,x=-4
Find the zeros of x^2-20=x
The zeros of x^2-20=x are x=5,x=-4