What are the solutions to the equation 3x^2+25x+42=0 ?

The solutions to the equation 3x^2+25x+42=0 are x=-7/3 ,x=-6

Find the zeros of 3x^2+25x+42=0

The zeros of 3x^2+25x+42=0 are x=-7/3 ,x=-6

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3 x^{2} + 25 x + 42 = 0

x = - \frac{7}{3}, x = - 6

Solution steps

3 x^{2} + 25 x + 42 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 25 \pm 2 5 ^{2} - 4 \cdot 3 \cdot 42}{2 \cdot 3}

2 5^{2} - 4 \cdot 3 \cdot 42 = 11

x_{1, 2} = \frac{- 25 \pm 11}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 25 + 11}{2 \cdot 3}, x_{2} = \frac{- 25 - 11}{2 \cdot 3}

x = \frac{- 25 + 11}{2 \cdot 3} : - \frac{7}{3}

x = \frac{- 25 - 11}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

x = - \frac{7}{3}, x = - 6

5 x^{2} - 23 x - 10 = 0

lo g_{2} (x) \geq 1 + lo g_{2} (2 - x)

2 x^{2} + 8 x - 6 = 0

16 \cdot 4

\frac{n ^{5}}{( - 2 n ^{4} ) ^{3}}

What are the solutions to the equation 3x^2+25x+42=0 ?
The solutions to the equation 3x^2+25x+42=0 are x=-7/3 ,x=-6
Find the zeros of 3x^2+25x+42=0
The zeros of 3x^2+25x+42=0 are x=-7/3 ,x=-6