What are the solutions to the equation 2x^2+8x-6=0 ?

The solutions to the equation 2x^2+8x-6=0 are x=-2+sqrt(7),x=-2-sqrt(7)

Find the zeros of 2x^2+8x-6=0

The zeros of 2x^2+8x-6=0 are x=-2+sqrt(7),x=-2-sqrt(7)

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2 x^{2} + 8 x - 6 = 0

x = - 2 + 7, x = - 2 - 7

Solution steps

2 x^{2} + 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

8^{2} - 4 \cdot 2 (- 6) = 47

x_{1, 2} = \frac{- 8 \pm 4 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4 7}{2 \cdot 2}, x_{2} = \frac{- 8 - 4 7}{2 \cdot 2}

x = \frac{- 8 + 4 7}{2 \cdot 2} : - 2 + 7

x = \frac{- 8 - 4 7}{2 \cdot 2} : - 2 - 7

The solutions to the quadratic equation are:

x = - 2 + 7, x = - 2 - 7

16 \cdot 4

\frac{n ^{5}}{( - 2 n ^{4} ) ^{3}}

(- 3 + 2 i)^{2}

5 y^{2} + 20 = 0

\frac{3}{4} x = 9

What are the solutions to the equation 2x^2+8x-6=0 ?
The solutions to the equation 2x^2+8x-6=0 are x=-2+sqrt(7),x=-2-sqrt(7)
Find the zeros of 2x^2+8x-6=0
The zeros of 2x^2+8x-6=0 are x=-2+sqrt(7),x=-2-sqrt(7)