What are the solutions to the equation (3k-1)^2=-8 ?

The solutions to the equation (3k-1)^2=-8 are k= 1/3+i(2sqrt(2))/3 ,k= 1/3-i(2sqrt(2))/3

Find the zeros of (3k-1)^2=-8

The zeros of (3k-1)^2=-8 are k= 1/3+i(2sqrt(2))/3 ,k= 1/3-i(2sqrt(2))/3

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(3 k - 1)^{2} = - 8

k = \frac{1}{3} + i \frac{2 2}{3}, k = \frac{1}{3} - i \frac{2 2}{3}

Solution steps

(3 k - 1)^{2} = - 8

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 k - 1 = - 8 : k = \frac{1}{3} + i \frac{2 2}{3}

Solve

3 k - 1 = - - 8 : k = \frac{1}{3} - i \frac{2 2}{3}

The solutions to the quadratic equation are:

k = \frac{1}{3} + i \frac{2 2}{3}, k = \frac{1}{3} - i \frac{2 2}{3}

4 r^{2} + 20 r + 25 = 0

\frac{2}{5} \cdot 20

\frac{- 9 y ^{2}}{5 x} \cdot \frac{- 10 x ^{2}}{3 y}

x^{2} + x + \frac{1}{4} = 0

x^{3} - 9 x^{2} + 108

What are the solutions to the equation (3k-1)^2=-8 ?
The solutions to the equation (3k-1)^2=-8 are k= 1/3+i(2sqrt(2))/3 ,k= 1/3-i(2sqrt(2))/3
Find the zeros of (3k-1)^2=-8
The zeros of (3k-1)^2=-8 are k= 1/3+i(2sqrt(2))/3 ,k= 1/3-i(2sqrt(2))/3