What are the solutions to the equation x^2+x+1/4 =0 ?

The solutions to the equation x^2+x+1/4 =0 are x=-1/2

Find the zeros of x^2+x+1/4 =0

The zeros of x^2+x+1/4 =0 are x=-1/2

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x^{2} + x + \frac{1}{4} = 0

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

x^{2} + x + \frac{1}{4} = 0

Multiply both sides by

4

4 x^{2} + 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

4^{2} - 4 \cdot 4 \cdot 1 = 0

x_{1, 2} = \frac{- 4 \pm 0}{2 \cdot 4}

x = \frac{- 4}{2 \cdot 4}

\frac{- 4}{2 \cdot 4} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

x^{3} - 9 x^{2} + 108

20 x^{2} - 7 x - 6 = 0

4 x^{8} - 61 x^{4} + 225

∣ x - 1 ∣ < - 4

34 x - 3 \leq 3 or 25 (x + 10) \geq 0

What are the solutions to the equation x^2+x+1/4 =0 ?
The solutions to the equation x^2+x+1/4 =0 are x=-1/2
Find the zeros of x^2+x+1/4 =0
The zeros of x^2+x+1/4 =0 are x=-1/2