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Popular >

34x-3<= 3\lor 25(x+10)>= 0

Solution

34 x - 3 \leq 3 or 25 (x + 10) \geq 0

Solution

True for all x

+1

Solution steps

34 x - 3 \leq 3 or 25 (x + 10) \geq 0

34 x - 3 \leq 3 : x \leq \frac{3}{17}

25 (x + 10) \geq 0 : x \geq - 10

Combine the intervals

x \leq \frac{3}{17} or x \geq - 10

Merge Overlapping Intervals

True for all x

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Frequently Asked Questions (FAQ)

What is 34x-3<= 3\lor 25(x+10)>= 0 ?
The solution to 34x-3<= 3\lor 25(x+10)>= 0 is True for all x