What are the solutions to the equation 9x+2=8x^2+6x ?

The solutions to the equation 9x+2=8x^2+6x are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)

Find the zeros of 9x+2=8x^2+6x

The zeros of 9x+2=8x^2+6x are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)

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9 x + 2 = 8 x^{2} + 6 x

x = \frac{3 + 73}{16}, x = \frac{3 - 73}{16}

Solution steps

9 x + 2 = 8 x^{2} + 6 x

Switch sides

8 x^{2} + 6 x = 9 x + 2

Move

2

to the left side

8 x^{2} + 6 x - 2 = 9 x

Move

9 x

to the left side

8 x^{2} - 3 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 8 ( - 2 )}{2 \cdot 8}

(- 3)^{2} - 4 \cdot 8 (- 2) = 73

x_{1, 2} = \frac{- ( - 3 ) \pm 73}{2 \cdot 8}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 73}{2 \cdot 8}, x_{2} = \frac{- ( - 3 ) - 73}{2 \cdot 8}

x = \frac{- ( - 3 ) + 73}{2 \cdot 8} : \frac{3 + 73}{16}

x = \frac{- ( - 3 ) - 73}{2 \cdot 8} : \frac{3 - 73}{16}

The solutions to the quadratic equation are:

x = \frac{3 + 73}{16}, x = \frac{3 - 73}{16}

2 x - 3 > 5 and 3 x - 1 > 11

12 \cdot 18

- 3 x^{2} - 15 x + 72 = 0

7 x^{4} - 343 y^{4}

- \frac{4}{7} \cdot 2

What are the solutions to the equation 9x+2=8x^2+6x ?
The solutions to the equation 9x+2=8x^2+6x are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)
Find the zeros of 9x+2=8x^2+6x
The zeros of 9x+2=8x^2+6x are x=(3+sqrt(73))/(16),x=(3-sqrt(73))/(16)