What is 1/2 (log_{6}(45)-log_{6}(5))+log_{6}(12) ?

The solution to 1/2 (log_{6}(45)-log_{6}(5))+log_{6}(12) is 2

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simplify 1/2 (log_{6}(45)-log_{6}(5))+log_{6}(12)

simplify

\frac{1}{2} (lo g_{6} (45) - lo g_{6} (5)) + lo g_{6} (12)

2

Solution steps

\frac{1}{2} (lo g_{6} (45) - lo g_{6} (5)) + lo g_{6} (12)

lo g_{6} (45) - lo g_{6} (5) = 2 lo g_{6} (3)

lo g_{6} (12) = 1 + lo g_{6} (2)

= \frac{1}{2} \cdot 2 lo g_{6} (3) + 1 + lo g_{6} (2)

\frac{1}{2} \cdot 2 lo g_{6} (3) = lo g_{6} (3)

= lo g_{6} (3) + 1 + lo g_{6} (2)

lo g_{6} (3) + lo g_{6} (2) = 1

= 1 + 1

Add the numbers:

1 + 1 = 2

= 2

- \infty + \infty

\frac{- 1}{i}

9 x^{2} + 9 x - 10 = 0

u^{2} - 4

(\frac{4}{5} + \frac{3}{5}) + 3.5 \cdot 5

What is 1/2 (log_{6}(45)-log_{6}(5))+log_{6}(12) ?
The solution to 1/2 (log_{6}(45)-log_{6}(5))+log_{6}(12) is 2