What is |-6b+4|-5<= 23 ?

The solution to |-6b+4|-5<= 23 is -4<= b<= 16/3

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|-6b+4|-5<= 23

∣ - 6 b + 4 ∣ - 5 \leq 23

- 4 \leq b \leq \frac{16}{3}

Solution steps

∣ - 6 b + 4 ∣ - 5 \leq 23

Move

5

to the right side

∣ - 6 b + 4 ∣ \leq 28

Apply absolute rule: If

∣ u ∣ \leq a, a > 0

then

- a \leq u \leq a

- 28 \leq - 6 b + 4 \leq 28

- 6 b + 4 \geq - 28 and - 6 b + 4 \leq 28

b \leq \frac{16}{3} and b \geq - 4

Merge Overlapping Intervals

- 4 \leq b \leq \frac{16}{3}

3 5^{2} + 1 2^{2} = c^{2}

ln (\frac{1}{5})

3 ∣ 5 y - 1 ∣ - 5 = 4

\frac{18}{21 m + 6}

\frac{1}{9} \cdot \frac{1}{9}