What are the solutions to the equation 9x^2+24x=-14 ?

The solutions to the equation 9x^2+24x=-14 are x=(-4+sqrt(2))/3 ,x=-(4+sqrt(2))/3

Find the zeros of 9x^2+24x=-14

The zeros of 9x^2+24x=-14 are x=(-4+sqrt(2))/3 ,x=-(4+sqrt(2))/3

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9 x^{2} + 24 x = - 14

x = \frac{- 4 + 2}{3}, x = - \frac{4 + 2}{3}

Decimal Notation

x = - 0.86192 \dots, x = - 1.80473 \dots

Solution steps

9 x^{2} + 24 x = - 14

Move

14

to the left side

9 x^{2} + 24 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 9 \cdot 14}{2 \cdot 9}

2 4^{2} - 4 \cdot 9 \cdot 14 = 62

x_{1, 2} = \frac{- 24 \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 24 + 6 2}{2 \cdot 9}, x_{2} = \frac{- 24 - 6 2}{2 \cdot 9}

x = \frac{- 24 + 6 2}{2 \cdot 9} : \frac{- 4 + 2}{3}

x = \frac{- 24 - 6 2}{2 \cdot 9} : - \frac{4 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 4 + 2}{3}, x = - \frac{4 + 2}{3}

\frac{2 - p}{p} \leq 2

∣ 5 x - 10 ∣ = 15

\frac{x ^{2}}{4} - \frac{x}{1} = \frac{5}{4}

15 x + 28 = 27 x + 4

- x^{2} = 0

What are the solutions to the equation 9x^2+24x=-14 ?
The solutions to the equation 9x^2+24x=-14 are x=(-4+sqrt(2))/3 ,x=-(4+sqrt(2))/3
Find the zeros of 9x^2+24x=-14
The zeros of 9x^2+24x=-14 are x=(-4+sqrt(2))/3 ,x=-(4+sqrt(2))/3