What are the solutions to the equation 3x^2-4x+4/3 =0 ?

The solutions to the equation 3x^2-4x+4/3 =0 are x= 2/3

Find the zeros of 3x^2-4x+4/3 =0

The zeros of 3x^2-4x+4/3 =0 are x= 2/3

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3 x^{2} - 4 x + \frac{4}{3} = 0

x = \frac{2}{3}

Decimal Notation

x = 0.66666 \dots

Solution steps

3 x^{2} - 4 x + \frac{4}{3} = 0

Multiply both sides by

3

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

\frac{- 8 x ^{0} y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}}

\frac{x - 5}{2 x + 7} \geq 1

4 (x - \frac{1}{2})^{2} - \frac{18}{4} = 0

- 9.67 d - (- 8.67 d + 5.43) = - 1.92

(\frac{3 x}{2 y})^{3}

What are the solutions to the equation 3x^2-4x+4/3 =0 ?
The solutions to the equation 3x^2-4x+4/3 =0 are x= 2/3
Find the zeros of 3x^2-4x+4/3 =0
The zeros of 3x^2-4x+4/3 =0 are x= 2/3