What are the solutions to the equation p^2+p-6=0 ?

The solutions to the equation p^2+p-6=0 are p=2,p=-3

Find the zeros of p^2+p-6=0

The zeros of p^2+p-6=0 are p=2,p=-3

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p^{2} + p - 6 = 0

p = 2, p = - 3

Solution steps

p^{2} + p - 6 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 6 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 6) = 5

p_{1, 2} = \frac{- 1 \pm 5}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- 1 + 5}{2 \cdot 1}, p_{2} = \frac{- 1 - 5}{2 \cdot 1}

p = \frac{- 1 + 5}{2 \cdot 1} : 2

p = \frac{- 1 - 5}{2 \cdot 1} : - 3

The solutions to the quadratic equation are:

p = 2, p = - 3

3 m + 58 = m^{2} + 12 m + 36

- (2 - 3 x) < 5 (4 - x)

- 3 (3 c + 5) = 2 (10 - c)

0.6 x - 0.3 = 0.1

9 x^{2} + 30 x + 16

What are the solutions to the equation p^2+p-6=0 ?
The solutions to the equation p^2+p-6=0 are p=2,p=-3
Find the zeros of p^2+p-6=0
The zeros of p^2+p-6=0 are p=2,p=-3