What is (-8x^0y^4z)/(-4x^8y^3z^3) ?

The solution to (-8x^0y^4z)/(-4x^8y^3z^3) is (2y)/(x^8z^2)

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simplify (-8x^0y^4z)/(-4x^8y^3z^3)

simplify

\frac{- 8 x ^{0} y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}}

\frac{2 y}{x ^{8} z ^{2}}

Solution steps

\frac{- 8 x ^{0} y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}}

Simplify

\frac{- 8 x ^{0} y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}} : \frac{- 8 y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}}

= \frac{- 8 y ^{4} z}{- 4 x ^{8} y ^{3} z ^{3}}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{8 y ^{4} z}{4 x ^{8} y ^{3} z ^{3}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 2 y ^{4} z}{4 x ^{8} y ^{3} z ^{3}}

Cancel the common factor:

4

= \frac{2 y ^{4} z}{x ^{8} y ^{3} z ^{3}}

Simplify

\frac{y ^{4}}{y ^{3}} : y

= \frac{2 yz}{x ^{8} z ^{3}}

Simplify

\frac{z}{z ^{3}} : \frac{1}{z ^{2}}

= \frac{2 y}{x ^{8} z ^{2}}

\frac{x - 5}{2 x + 7} \geq 1

4 (x - \frac{1}{2})^{2} - \frac{18}{4} = 0

- 9.67 d - (- 8.67 d + 5.43) = - 1.92

(\frac{3 x}{2 y})^{3}

(2 x - 1) (2 x + 3) = 2 (2 x^{2} - x + 1)

What is (-8x^0y^4z)/(-4x^8y^3z^3) ?
The solution to (-8x^0y^4z)/(-4x^8y^3z^3) is (2y)/(x^8z^2)