What are the solutions to the equation 4(x-1/2)^2-18/4 =0 ?

The solutions to the equation 4(x-1/2)^2-18/4 =0 are x= 3/(2sqrt(2))+1/2 ,x=-3/(2sqrt(2))+1/2

Find the zeros of 4(x-1/2)^2-18/4 =0

The zeros of 4(x-1/2)^2-18/4 =0 are x= 3/(2sqrt(2))+1/2 ,x=-3/(2sqrt(2))+1/2

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4 (x - \frac{1}{2})^{2} - \frac{18}{4} = 0

x = \frac{3}{2 2} + \frac{1}{2}, x = - \frac{3}{2 2} + \frac{1}{2}

Solution steps

4 (x - \frac{1}{2})^{2} - \frac{18}{4} = 0

Move

\frac{18}{4}

to the right side

4 (x - \frac{1}{2})^{2} = \frac{9}{2}

Divide both sides by

4

(x - \frac{1}{2})^{2} = \frac{9}{8}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - \frac{1}{2} = \frac{9}{8} : x = \frac{3}{2 2} + \frac{1}{2}

Solve

x - \frac{1}{2} = - \frac{9}{8} : x = - \frac{3}{2 2} + \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2 2} + \frac{1}{2}, x = - \frac{3}{2 2} + \frac{1}{2}

- 9.67 d - (- 8.67 d + 5.43) = - 1.92

(\frac{3 x}{2 y})^{3}

(2 x - 1) (2 x + 3) = 2 (2 x^{2} - x + 1)

p^{2} + p - 6 = 0

3 m + 58 = m^{2} + 12 m + 36

What are the solutions to the equation 4(x-1/2)^2-18/4 =0 ?
The solutions to the equation 4(x-1/2)^2-18/4 =0 are x= 3/(2sqrt(2))+1/2 ,x=-3/(2sqrt(2))+1/2
Find the zeros of 4(x-1/2)^2-18/4 =0
The zeros of 4(x-1/2)^2-18/4 =0 are x= 3/(2sqrt(2))+1/2 ,x=-3/(2sqrt(2))+1/2