What is (\frac{m+3)/(m^2-16)}{(m^2-9)/(m+4)} ?

The solution to (\frac{m+3)/(m^2-16)}{(m^2-9)/(m+4)} is 1/((m-4)(m-3))

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simplify (\frac{m+3)/(m^2-16)}{(m^2-9)/(m+4)}

simplify

\frac{\frac{m + 3}{m ^{2} - 16}}{\frac{m ^{2} - 9}{m + 4}}

\frac{1}{( m - 4 ) ( m - 3 )}

Solution steps

\frac{\frac{m + 3}{m ^{2} - 16}}{\frac{m ^{2} - 9}{m + 4}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( m + 3 ) ( m + 4 )}{( m ^{2} - 16 ) ( m ^{2} - 9 )}

Cancel

\frac{( m + 3 ) ( m + 4 )}{( m ^{2} - 16 ) ( m ^{2} - 9 )} : \frac{1}{( m - 4 ) ( m - 3 )}

= \frac{1}{( m - 4 ) ( m - 3 )}

3 2^{\frac{1}{5}}

4 x^{2} + 9 x - 2 = 0

\frac{x + 1}{2} = 3

\frac{3 - 10 i}{5 i}

2 x^{3} + 11 x^{2} - 20 x + 7

What is (\frac{m+3)/(m^2-16)}{(m^2-9)/(m+4)} ?
The solution to (\frac{m+3)/(m^2-16)}{(m^2-9)/(m+4)} is 1/((m-4)(m-3))