What is the answer to log_{2}(8)=3b+1 ?

The answer to log_{2}(8)=3b+1 is b= 2/3

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log_{2}(8)=3b+1

lo g_{2} (8) = 3 b + 1

b = \frac{2}{3}

Solution steps

lo g_{2} (8) = 3 b + 1

Switch sides

3 b + 1 = lo g_{2} (8)

Move

1

to the right side

3 b = 2

Divide both sides by

3

b = \frac{2}{3}

(2 + 10) (2 - 10)

e^{- \frac{π}{2}}

(\frac{a ^{2}}{b})^{7} (\frac{a ^{2} b ^{2}}{c ^{3}})^{4}

lo g_{2} (x) < 0

3 x - 10 = 11