What is ((a^2)/b)^7((a^2b^2)/(c^3))^4 ?

The solution to ((a^2)/b)^7((a^2b^2)/(c^3))^4 is (a^{22}b)/(c^{12)}

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simplify ((a^2)/b)^7((a^2b^2)/(c^3))^4

simplify

(\frac{a ^{2}}{b})^{7} (\frac{a ^{2} b ^{2}}{c ^{3}})^{4}

\frac{a ^{22} b}{c ^{12}}

Solution steps

(\frac{a ^{2}}{b})^{7} (\frac{a ^{2} b ^{2}}{c ^{3}})^{4}

Simplify

(\frac{a ^{2}}{b})^{7} : \frac{a ^{14}}{b ^{7}}

= \frac{a ^{14}}{b ^{7}} (\frac{a ^{2} b ^{2}}{c ^{3}})^{4}

Simplify

(\frac{a ^{2} b ^{2}}{c ^{3}})^{4} : \frac{a ^{8} b ^{8}}{c ^{12}}

= \frac{a ^{14}}{b ^{7}} \cdot \frac{a ^{8} b ^{8}}{c ^{12}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{a ^{14} a ^{8} b ^{8}}{b ^{7} c ^{12}}

Simplify

\frac{b ^{8}}{b ^{7}} : b

= \frac{a ^{14} a ^{8} b}{c ^{12}}

Simplify

a^{14} a^{8} : a^{22}

= \frac{a ^{22} b}{c ^{12}}

lo g_{2} (x) < 0

3 x - 10 = 11

32 = - 4 a + 36

x^{2} - 29 = 0

e^{l o g_{e^{2}} (16)}

What is ((a^2)/b)^7((a^2b^2)/(c^3))^4 ?
The solution to ((a^2)/b)^7((a^2b^2)/(c^3))^4 is (a^{22}b)/(c^{12)}