What are the solutions to the equation x^2-3x-5=2x+9 ?

The solutions to the equation x^2-3x-5=2x+9 are x=7,x=-2

Find the zeros of x^2-3x-5=2x+9

The zeros of x^2-3x-5=2x+9 are x=7,x=-2

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x^{2} - 3 x - 5 = 2 x + 9

x = 7, x = - 2

Solution steps

x^{2} - 3 x - 5 = 2 x + 9

Move

9

to the left side

x^{2} - 3 x - 14 = 2 x

Move

2 x

to the left side

x^{2} - 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 14 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 14) = 9

x_{1, 2} = \frac{- ( - 5 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 9}{2 \cdot 1}

x = \frac{- ( - 5 ) + 9}{2 \cdot 1} : 7

x = \frac{- ( - 5 ) - 9}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

x = 7, x = - 2

i^{12}

s^{2} - 6 s + 18 = 0

\frac{7}{4} + \frac{1}{4}

∣ 2 x + 1 ∣ < 0

lo g_{\frac{1}{2}} (16) = x

What are the solutions to the equation x^2-3x-5=2x+9 ?
The solutions to the equation x^2-3x-5=2x+9 are x=7,x=-2
Find the zeros of x^2-3x-5=2x+9
The zeros of x^2-3x-5=2x+9 are x=7,x=-2