What are the solutions to the equation s^2-6s+18=0 ?

The solutions to the equation s^2-6s+18=0 are s=3+3i,s=3-3i

Find the zeros of s^2-6s+18=0

The zeros of s^2-6s+18=0 are s=3+3i,s=3-3i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

s^{2} - 6 s + 18 = 0

s = 3 + 3 i, s = 3 - 3 i

Solution steps

s^{2} - 6 s + 18 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

Simplify

(- 6)^{2} - 4 \cdot 1 \cdot 18 : 6 i

s_{1, 2} = \frac{- ( - 6 ) \pm 6 i}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 6 ) + 6 i}{2 \cdot 1}, s_{2} = \frac{- ( - 6 ) - 6 i}{2 \cdot 1}

s = \frac{- ( - 6 ) + 6 i}{2 \cdot 1} : 3 + 3 i

s = \frac{- ( - 6 ) - 6 i}{2 \cdot 1} : 3 - 3 i

The solutions to the quadratic equation are:

s = 3 + 3 i, s = 3 - 3 i

\frac{7}{4} + \frac{1}{4}

∣ 2 x + 1 ∣ < 0

lo g_{\frac{1}{2}} (16) = x

x \cdot x^{- 3}

x^{2} - 20 x = 20 x + 100

What are the solutions to the equation s^2-6s+18=0 ?
The solutions to the equation s^2-6s+18=0 are s=3+3i,s=3-3i
Find the zeros of s^2-6s+18=0
The zeros of s^2-6s+18=0 are s=3+3i,s=3-3i