What are the solutions to the equation x^2-20x=20x+100 ?

The solutions to the equation x^2-20x=20x+100 are x=10(2+sqrt(5)),x=10(2-sqrt(5))

Find the zeros of x^2-20x=20x+100

The zeros of x^2-20x=20x+100 are x=10(2+sqrt(5)),x=10(2-sqrt(5))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 20 x = 20 x + 100

x = 10 (2 + 5), x = 10 (2 - 5)

Decimal Notation

x = 42.36067 \dots, x = - 2.36067 \dots

Solution steps

x^{2} - 20 x = 20 x + 100

Move

100

to the left side

x^{2} - 20 x - 100 = 20 x

Move

20 x

to the left side

x^{2} - 40 x - 100 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 40 ) \pm ( - 40 ) ^{2} - 4 \cdot 1 \cdot ( - 100 )}{2 \cdot 1}

(- 40)^{2} - 4 \cdot 1 \cdot (- 100) = 205

x_{1, 2} = \frac{- ( - 40 ) \pm 20 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 40 ) + 20 5}{2 \cdot 1}, x_{2} = \frac{- ( - 40 ) - 20 5}{2 \cdot 1}

x = \frac{- ( - 40 ) + 20 5}{2 \cdot 1} : 10 (2 + 5)

x = \frac{- ( - 40 ) - 20 5}{2 \cdot 1} : 10 (2 - 5)

The solutions to the quadratic equation are:

x = 10 (2 + 5), x = 10 (2 - 5)

9 g^{2} + 30 g + 25

3 x^{2} - 5 x - 7 = 0

0.05 = (1 + \frac{r}{2})^{2} - 1

- x^{2} + 4 x - 7 < 0

5 6^{2}

What are the solutions to the equation x^2-20x=20x+100 ?
The solutions to the equation x^2-20x=20x+100 are x=10(2+sqrt(5)),x=10(2-sqrt(5))
Find the zeros of x^2-20x=20x+100
The zeros of x^2-20x=20x+100 are x=10(2+sqrt(5)),x=10(2-sqrt(5))