What are the solutions to the equation 3x^2-5x-7=0 ?

The solutions to the equation 3x^2-5x-7=0 are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6

Find the zeros of 3x^2-5x-7=0

The zeros of 3x^2-5x-7=0 are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6

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3 x^{2} - 5 x - 7 = 0

x = \frac{5 + 109}{6}, x = \frac{5 - 109}{6}

Solution steps

3 x^{2} - 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 3 ( - 7 )}{2 \cdot 3}

(- 5)^{2} - 4 \cdot 3 (- 7) = 109

x_{1, 2} = \frac{- ( - 5 ) \pm 109}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 109}{2 \cdot 3}, x_{2} = \frac{- ( - 5 ) - 109}{2 \cdot 3}

x = \frac{- ( - 5 ) + 109}{2 \cdot 3} : \frac{5 + 109}{6}

x = \frac{- ( - 5 ) - 109}{2 \cdot 3} : \frac{5 - 109}{6}

The solutions to the quadratic equation are:

x = \frac{5 + 109}{6}, x = \frac{5 - 109}{6}

0.05 = (1 + \frac{r}{2})^{2} - 1

- x^{2} + 4 x - 7 < 0

5 6^{2}

x^{2} + 21 x + 110

x^{2} - 49 < 0

What are the solutions to the equation 3x^2-5x-7=0 ?
The solutions to the equation 3x^2-5x-7=0 are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6
Find the zeros of 3x^2-5x-7=0
The zeros of 3x^2-5x-7=0 are x=(5+sqrt(109))/6 ,x=(5-sqrt(109))/6