What is y/4+2-(y+1)/6 >= (y+5)/9 ?

The solution to y/4+2-(y+1)/6 >= (y+5)/9 is y<= 46

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y/4+2-(y+1)/6 >= (y+5)/9

\frac{y}{4} + 2 - \frac{y + 1}{6} \geq \frac{y + 5}{9}

y \leq 46

Interval Notation

(- \infty, 46]

Solution steps

\frac{y}{4} + 2 - \frac{y + 1}{6} \geq \frac{y + 5}{9}

Multiply by LCM

9 y + 72 - 6 (y + 1) \geq 4 (y + 5)

Expand

9 y + 72 - 6 (y + 1) : 3 y + 66

Expand

4 (y + 5) : 4 y + 20

3 y + 66 \geq 4 y + 20

Move

66

to the right side

3 y \geq 4 y - 46

Move

4 y

to the left side

- y \geq - 46

Multiply both sides by

- 1

y \leq 46

4 m^{2} + 76 = 0

3 y = 3

\frac{( x ^{2} y ^{3} ) ( x y ) ^{- 8}}{x ^{2} y}

\frac{2 n - 8}{n ^{2} - 16}

(\frac{1}{3})^{- 0}

What is y/4+2-(y+1)/6 >= (y+5)/9 ?
The solution to y/4+2-(y+1)/6 >= (y+5)/9 is y<= 46