What are the solutions to the equation 602^2+724^2=c^2 ?

The solutions to the equation 602^2+724^2=c^2 are c=2sqrt(221645),c=-2sqrt(221645)

Find the zeros of 602^2+724^2=c^2

The zeros of 602^2+724^2=c^2 are c=2sqrt(221645),c=-2sqrt(221645)

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60 2^{2} + 72 4^{2} = c^{2}

c = 2221645, c = - 2221645

Solution steps

60 2^{2} + 72 4^{2} = c^{2}

Switch sides

c^{2} = 60 2^{2} + 72 4^{2}

Simplify

60 2^{2} + 72 4^{2} : 886580

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 886580, c = - 886580

886580 = 2221645

- 886580 = - 2221645

c = 2221645, c = - 2221645

6 x^{2} + 4 x - 1 = 0

x^{2} + 4 x = 96

4 x^{2} = 22 x + 42

3 x - \frac{5}{2} > \frac{1}{2} x

What are the solutions to the equation 602^2+724^2=c^2 ?
The solutions to the equation 602^2+724^2=c^2 are c=2sqrt(221645),c=-2sqrt(221645)
Find the zeros of 602^2+724^2=c^2
The zeros of 602^2+724^2=c^2 are c=2sqrt(221645),c=-2sqrt(221645)