What are the solutions to the equation x^2+1/4 x-4=0 ?

The solutions to the equation x^2+1/4 x-4=0 are x=(-1+sqrt(257))/8 ,x=(-1-sqrt(257))/8

Find the zeros of x^2+1/4 x-4=0

The zeros of x^2+1/4 x-4=0 are x=(-1+sqrt(257))/8 ,x=(-1-sqrt(257))/8

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x^{2} + \frac{1}{4} x - 4 = 0

x = \frac{- 1 + 257}{8}, x = \frac{- 1 - 257}{8}

Decimal Notation

x = 1.87890 \dots, x = - 2.12890 \dots

Solution steps

x^{2} + \frac{1}{4} x - 4 = 0

Multiply both sides by

4

4 x^{2} + x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 4 ( - 16 )}{2 \cdot 4}

1^{2} - 4 \cdot 4 (- 16) = 257

x_{1, 2} = \frac{- 1 \pm 257}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 1 + 257}{2 \cdot 4}, x_{2} = \frac{- 1 - 257}{2 \cdot 4}

x = \frac{- 1 + 257}{2 \cdot 4} : \frac{- 1 + 257}{8}

x = \frac{- 1 - 257}{2 \cdot 4} : \frac{- 1 - 257}{8}

The solutions to the quadratic equation are:

x = \frac{- 1 + 257}{8}, x = \frac{- 1 - 257}{8}

25 + \frac{36}{1 + 0.6 ( 0.7 ) ^{- 10}}

31 p^{2} + 10 p + 1 = 6 p^{2}

w (w + 2) = - 5

3 ∣ 9 b - 1 ∣ - 10 = - 10

∣ 3 x - 19 ∣ = - 11

What are the solutions to the equation x^2+1/4 x-4=0 ?
The solutions to the equation x^2+1/4 x-4=0 are x=(-1+sqrt(257))/8 ,x=(-1-sqrt(257))/8
Find the zeros of x^2+1/4 x-4=0
The zeros of x^2+1/4 x-4=0 are x=(-1+sqrt(257))/8 ,x=(-1-sqrt(257))/8