What are the solutions to the equation 5x^2+10=310 ?

The solutions to the equation 5x^2+10=310 are x=2sqrt(15),x=-2sqrt(15)

Find the zeros of 5x^2+10=310

The zeros of 5x^2+10=310 are x=2sqrt(15),x=-2sqrt(15)

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5 x^{2} + 10 = 310

x = 215, x = - 215

Decimal Notation

x = 7.74596 \dots, x = - 7.74596 \dots

Solution steps

5 x^{2} + 10 = 310

Move

10

to the right side

5 x^{2} = 300

Divide both sides by

5

x^{2} = 60

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 60, x = - 60

60 = 215

- 60 = - 215

x = 215, x = - 215

x^{2} = 15 x

\frac{2}{5}

f (a) = \frac{a ^{2} + a - 42}{a ^{2} - a - 30}

x^{2} - 12 = 11 x

3 x + 5 > - 1 or - 2 x - 7 > 5

What are the solutions to the equation 5x^2+10=310 ?
The solutions to the equation 5x^2+10=310 are x=2sqrt(15),x=-2sqrt(15)
Find the zeros of 5x^2+10=310
The zeros of 5x^2+10=310 are x=2sqrt(15),x=-2sqrt(15)