What are the solutions to the equation x^2-17x+64=-6 ?

The solutions to the equation x^2-17x+64=-6 are x=10,x=7

Find the zeros of x^2-17x+64=-6

The zeros of x^2-17x+64=-6 are x=10,x=7

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x^{2} - 17 x + 64 = - 6

x = 10, x = 7

Solution steps

x^{2} - 17 x + 64 = - 6

Move

6

to the left side

x^{2} - 17 x + 70 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 17 ) \pm ( - 17 ) ^{2} - 4 \cdot 1 \cdot 70}{2 \cdot 1}

(- 17)^{2} - 4 \cdot 1 \cdot 70 = 3

x_{1, 2} = \frac{- ( - 17 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 17 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 17 ) - 3}{2 \cdot 1}

x = \frac{- ( - 17 ) + 3}{2 \cdot 1} : 10

x = \frac{- ( - 17 ) - 3}{2 \cdot 1} : 7

The solutions to the quadratic equation are:

x = 10, x = 7

x^{2} - 1 - 3 > 2

- 5 x + 13 \geq - 7

- 5 \leq 3 x - 2 < 7

9 n^{2} - 23 n + 20 = 3 n^{2}

x^{3} - 6 x^{2} + 5 x + 12

What are the solutions to the equation x^2-17x+64=-6 ?
The solutions to the equation x^2-17x+64=-6 are x=10,x=7
Find the zeros of x^2-17x+64=-6
The zeros of x^2-17x+64=-6 are x=10,x=7