What are the solutions to the equation 9n^2-23n+20=3n^2 ?

The solutions to the equation 9n^2-23n+20=3n^2 are n= 5/2 ,n= 4/3

Find the zeros of 9n^2-23n+20=3n^2

The zeros of 9n^2-23n+20=3n^2 are n= 5/2 ,n= 4/3

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9 n^{2} - 23 n + 20 = 3 n^{2}

n = \frac{5}{2}, n = \frac{4}{3}

Decimal Notation

n = 2.5, n = 1.33333 \dots

Solution steps

9 n^{2} - 23 n + 20 = 3 n^{2}

Move

3 n^{2}

to the left side

6 n^{2} - 23 n + 20 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 23 ) \pm ( - 23 ) ^{2} - 4 \cdot 6 \cdot 20}{2 \cdot 6}

(- 23)^{2} - 4 \cdot 6 \cdot 20 = 7

n_{1, 2} = \frac{- ( - 23 ) \pm 7}{2 \cdot 6}

Separate the solutions

n_{1} = \frac{- ( - 23 ) + 7}{2 \cdot 6}, n_{2} = \frac{- ( - 23 ) - 7}{2 \cdot 6}

n = \frac{- ( - 23 ) + 7}{2 \cdot 6} : \frac{5}{2}

n = \frac{- ( - 23 ) - 7}{2 \cdot 6} : \frac{4}{3}

The solutions to the quadratic equation are:

n = \frac{5}{2}, n = \frac{4}{3}

x^{3} - 6 x^{2} + 5 x + 12

4 (2 x - 3) - 2 (3 x - 1) = - 14

128 n^{2} - 224 n + 98

8 y^{6} + 27

2 x^{3} - 19 x + 3

What are the solutions to the equation 9n^2-23n+20=3n^2 ?
The solutions to the equation 9n^2-23n+20=3n^2 are n= 5/2 ,n= 4/3
Find the zeros of 9n^2-23n+20=3n^2
The zeros of 9n^2-23n+20=3n^2 are n= 5/2 ,n= 4/3