What are the solutions to the equation 4x^2=12x-9 ?

The solutions to the equation 4x^2=12x-9 are x= 3/2

Find the zeros of 4x^2=12x-9

The zeros of 4x^2=12x-9 are x= 3/2

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4 x^{2} = 12 x - 9

x = \frac{3}{2}

Solution steps

4 x^{2} = 12 x - 9

Move

9

to the left side

4 x^{2} + 9 = 12 x

Move

12 x

to the left side

4 x^{2} + 9 - 12 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 12 x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

x = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

x = \frac{3}{2}

The solution to the quadratic equation is:

x = \frac{3}{2}

7 x^{3} - 7 x

6 m^{2} - 5 m - 6

(s^{2} + 3 s + 2) (2 s - 8) - (s^{2} - 8 s + 15) (2 s + 3) = 0

5 y = 2 y^{2} + 2

ln (8) - ln (4)

What are the solutions to the equation 4x^2=12x-9 ?
The solutions to the equation 4x^2=12x-9 are x= 3/2
Find the zeros of 4x^2=12x-9
The zeros of 4x^2=12x-9 are x= 3/2